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Proof step 5 from proof abs-sub-01 (previous step)

~2 < i0 ⊦ ~1 = i0, abs(i0) < abs(2 + i0)

Heuristic weak cut applied rule cut formula

And obtained the following new goals

Proof step 6:
~2 < i0 ⊦ i0 + 2 < 0, ~1 = i0, abs(i0) < abs(2 + i0)

Rule argument

fma: i0 + 2 < 0

Additional information

Used simplifier rules: numls-03: ⊦ i + (* j) < (* j0) ↔ i < j0 - j;%ls-01: ⊦ i < j → ¬ j < i; from specification int-basic1%add-a: ⊦ i + j + i0 = (i + j) + i0; from specification int-basic2%add-c: ⊦ i + j = j + i; from specification int-basic2 Used formulas: i0 + 2 < 0