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Proof step 2 from proof abseq (previous step)

⊦ abs(i) + i = 0, 0 < i

Heuristic weak cut applied rule cut formula

And closed the goal!

Rule argument

fma: i < 0

Additional information

Used simplifier rules: abs-08: ⊦ i < 0 → abs(i) = ~ i;%Minus-def: ⊦ ~ i = 0 - i;%sub-zero: ⊦ i + (0 - i0) = i - i0;%sub-sub-03: ⊦ i - i = 0;%Abs-pos: ⊦ ¬ j < 0 → abs(j) = j;%zero-07: ⊦ i + i = 0 ↔ i = 0; from specification int-basic2%lst-01: ⊦ ¬ i < j → (i ≠ j ↔ j < i); from specification int-basic1%add-a: ⊦ i + j + i0 = (i + j) + i0; from specification int-basic2%add-c: ⊦ i + j = j + i; from specification int-basic2 Used formulas: i < 0