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Proof step 2 from proof absls-01 (previous step)

abs(i) < i ⊦

Heuristic weak cut applied rule cut formula

And closed the goal!

Rule argument

fma: i < 0

Additional information

Used simplifier rules: abs-08: ⊦ i < 0 → abs(i) = ~ i;%Minus-def: ⊦ ~ i = 0 - i;%sub-ls: ⊦ i - j < i0 ↔ i < j + i0;%Abs-pos: ⊦ ¬ j < 0 → abs(j) = j;%irref: ⊦ ¬ i < i; from specification int-basic1%ls-zero: ⊦ i < 0 ∧ j < 0 → ¬ 0 < i + j; from specification int-basic2%add-a: ⊦ i + j + i0 = (i + j) + i0; from specification int-basic2%add-c: ⊦ i + j = j + i; from specification int-basic2 Used formulas: i < 0