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Proof step 4 from proof absone-01 (previous step)

~2 = j + i, j < 0, i < 0 ⊦ j = ~1, i = 0

User applied rule cut formula

And closed the goal!

Rule argument

fma: j = ~2 - i

Additional information

Used simplifier rules: sub-add-01: ⊦ i + (j - i0) = i + j - i0;%minus-add: i < 0 ⊦ (* i) + j = j - ~ i;%sub-sub: ⊦ i - j - i0 = i - j + i0;%sub-add-09: ⊦ i - j + i = ~ j;%sub-eq: ⊦ i - j = i0 ↔ i = i0 + j;%mone-01: ⊦ i + ~1 = i - 1;%sub-ls: ⊦ i - j < i0 ↔ i < j + i0;%sub-eq: ⊦ i - j = i0 ↔ i = i0 + j;%add-a: ⊦ i + j + i0 = (i + j) + i0; from specification int-basic2%add-c: ⊦ i + j = j + i; from specification int-basic2%add-zero-rev: ⊦ 0 + i = i; from specification int-basic2%minus-one: ⊦ i < 0 → (~2 < i ↔ i = ~1); from specification int-basic1 Used formulas: j = ~2 - i