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Proof step 4 from proof int-simp-06 (previous step)

i1 + i3 < i + i2, ∃ i0. i1 = i + i0 ∧ 0 < i0 ⊦ i3 < i2

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 5:
i0 + i3 < i2, 0 < i0 ⊦ i3 < i2

Rule argument

Additional information

Used simplifier rules: forward-le-05: ⊦ i < j ∧ 0 ≤ i → 0 < j;%add-c: ⊦ i + j = j + i; from specification int-basic2%add-a: ⊦ i + j + i0 = (i + j) + i0; from specification int-basic2%ls-01: ⊦ i + j < i + i0 ↔ j < i0; from specification int-basic2