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Proof step 1 from proof k-sub-rec2 (conclusion)

⊦ j < 0 ∧ i = i0 -1 → i - j = i0 - j +1

Heuristic simplifier applied rule simplifier

And closed the goal!

Rule argument

Additional information

Used simplifier rules: sub-pred: ⊦ i -1 = i - 1;%sub-sub: ⊦ i - j - i0 = i - j + i0;%sub-eq: ⊦ i - j = i0 ↔ i = i0 + j;%sub-add-01: ⊦ i + (j - i0) = i + j - i0;%sub-add-06: ⊦ i + j - i0 + j = i - i0;%sub-add: ⊦ i + j - i = j;%add-c: ⊦ i + j = j + i; from specification int-basic2%add-a: ⊦ i + j + i0 = (i + j) + i0; from specification int-basic2%succ-01: ⊦ i +1 = i + 1; from specification int-basic2