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Proof step 1 from proof le-add-03 (conclusion)

⊦ i ≤ i0 ∧ j0 ≥ 0 → i ≤ i0 + j0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 2:
i0 + j0 < i ⊦ i0 < i, j0 < 0

Rule argument

Additional information

Used simplifier rules: le-def: ⊦ i ≤ j ↔ ¬ j < i;%ge-def: ⊦ i ≥ j ↔ ¬ i < j;