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Proof step 1 from proof le-add-06 (conclusion)

⊦ 0 ≤ i ∧ i0 + i + i1 ≤ i2 → ¬ i + i2 < i1 + i0

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 2:
⊦ ¬ i < j ↔ j ≤ i
Proof step 3:
⊦ 0 ≤ i ∧ i0 + i + i1 ≤ i2 → ¬ ¬ i1 + i0 ≤ i + i2

Rule argument

spec: int-abs inst: name: lels seq: ⊦ ¬ i < j ↔ j ≤ i subst: [j, i] → [i1 + i0, i + i2] flags: rewrite, current

Additional information

Used terms: i1 + i0, i + i2