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Proof step 1 from proof le-add-07 (conclusion)

⊦ 0 ≤ i ∧ 0 < i0 ∧ i0 + i2 + j ≤ i1 → ¬ i + i1 < j + i2

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 2:
⊦ ¬ i < j ↔ j ≤ i
Proof step 3:
⊦ 0 ≤ i ∧ 0 < i0 ∧ i0 + i2 + j ≤ i1 → ¬ ¬ j + i2 ≤ i + i1

Rule argument

spec: int-abs inst: name: lels seq: ⊦ ¬ i < j ↔ j ≤ i subst: [j, i] → [j + i2, i + i1] flags: rewrite, current

Additional information

Used terms: j + i2, i + i1