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Proof step 2 from proof le-three (previous step)

1 < i, 0 < i, i < 3 ⊦ i = 2

User applied rule insert rewrite lemma

And obtained the following new goals

Rule argument

spec: int-basic1 inst: name: lst-01 seq: ⊦ ¬ i < j → (i ≠ j ↔ j < i) subst: [j, i] → [2, i] flags: rewrite

Additional information

Used simplifier rules: num-between: i + 1 = i0 ⊦ j < (* i0) → ¬ (* i) < j; from specification int-basic2%two-ls: ⊦ 0 < j → (j < 2 ↔ j = 1); from specification int-basic1%lf-02: ⊦ i < j ∧ j = i0 → i < i0; (forward) from specification int-basic1 Used terms: 2, i