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Proof step 1 from proof ler (conclusion)

⊦ i ≤ i

Heuristic structural induction applied rule structural induction

And closed the goal!

Rule argument

term: i

Additional information

Used simplifier rules: le-def: ⊦ i ≤ j ↔ ¬ j < i;%numle-01: ⊦ i + (* j) ≤ i0 + (* j0) ↔ i ≤ i0 + (j0 - j);%le-def: ⊦ i ≤ j ↔ ¬ j < i;%sub-pred: ⊦ i -1 = i - 1;%sub-le: ⊦ i - j ≤ i0 ↔ i ≤ j + i0;%sub-add-01: ⊦ i + (j - i0) = i + j - i0;%numsub: ⊦ (* i) + i0 - (* j) = (i - j) + i0;%int generated by 0, +1, -1;;%irref: ⊦ ¬ i < i; from specification int-basic1%add-zero-rev: ⊦ 0 + i = i; from specification int-basic2%add-a: ⊦ i + j + i0 = (i + j) + i0; from specification int-basic2%add-c: ⊦ i + j = j + i; from specification int-basic2%succ-01: ⊦ i +1 = i + 1; from specification int-basic2