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Proof step 1 from proof minus-01 (conclusion)

⊦ ~(i + 1) = ~ i - 1

Heuristic simplifier applied rule simplifier

And closed the goal!

Rule argument

Additional information

Used simplifier rules: Minus-def: ⊦ ~ i = 0 - i;%num-subadd: ⊦ (* i) - j + (* i0) = i - i0 - j;%sub-sub: ⊦ i - j - i0 = i - j + i0;%sub-eq: ⊦ i - j = i0 ↔ i = i0 + j;%sub-add-01: ⊦ i + (j - i0) = i + j - i0;%mone-01: ⊦ i + ~1 = i - 1;%sub-add-09: ⊦ i - j + i = ~ j;%add-c: ⊦ i + j = j + i; from specification int-basic2%add-a: ⊦ i + j + i0 = (i + j) + i0; from specification int-basic2