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Proof step 1 from proof minus (conclusion)

⊦ ~(~ i - 1) = i + 1

Heuristic simplifier applied rule simplifier

And closed the goal!

Rule argument

Additional information

Used simplifier rules: Minus-def: ⊦ ~ i = 0 - i;%sub-sub: ⊦ i - j - i0 = i - j + i0;%num-subadd: ⊦ (* i) - j + (* i0) = i - i0 - j;%minus-sub: ⊦ ~(i - j) = j - i;%minus-neg: j < 0 ⊦ i - (* j) = i + ~ j;%numadd: ⊦ i + (* j) = i0 + (* j0) ↔ i = i0 + (j0 - j);%add-zero-rev: ⊦ 0 + i = i; from specification int-basic2%add-c: ⊦ i + j = j + i; from specification int-basic2%add-a: ⊦ i + j + i0 = (i + j) + i0; from specification int-basic2