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Proof step 2 from proof numle-02 (previous step)

⊦ j ≤ i0 + j0 ↔ j - j0 ≤ i0

Heuristic simplifier applied rule simplifier

And closed the goal!

Rule argument

Additional information

Used simplifier rules: le-def: ⊦ i ≤ j ↔ ¬ j < i;%sub-le: ⊦ i - j ≤ i0 ↔ i ≤ j + i0;%add-c: ⊦ i + j = j + i; from specification int-basic2