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Proof step 2 from proof numle-03 (
previous step
)
⊦ i + j ≤ j0 ↔ i ≤ j0 - j
Heuristic simplifier applied rule simplifier
And closed the goal!
Rule argument
Additional information
Used simplifier rules: le-def: ⊦ i ≤ j ↔ ¬ j < i;%sub-le-01: ⊦ i ≤ j - i0 ↔ i + i0 ≤ j;