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Proof step 3 from proof ple-01 (previous step)

∀ j, i0, j0. i1 < j → i1 + i0 < j + j0 ∨ j0 < i0, i1 +1 < j ⊦ i1 +1 + i0 < j + j0, j0 < i0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

Additional information

Used simplifier rules: add-a: ⊦ i + j + i0 = (i + j) + i0; from specification int-basic2%succ-01: ⊦ i +1 = i + 1; from specification int-basic2