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Proof step 1 from proof ple (conclusion)

i ≤ j, i0 ≤ j0 ⊦ i + i0 ≤ j + j0

Heuristic simplifier applied rule simplifier

And closed the goal!

Rule argument

Additional information

Used simplifier rules: le-def: ⊦ i ≤ j ↔ ¬ j < i;%add-c: ⊦ i + j = j + i; from specification int-basic2%add-a: ⊦ i + j + i0 = (i + j) + i0; from specification int-basic2%nls: ⊦ ¬ i < j ∧ ¬ i0 < j0 → ¬ i + i0 < j + j0; from specification int-basic2