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Proof step 1 from proof pls (conclusion)

j0 < i + j, j ≤ j0 ⊦ j0 < i + j0

Heuristic simplifier applied rule simplifier

And closed the goal!

Rule argument

Additional information

Used simplifier rules: le-def: ⊦ i ≤ j ↔ ¬ j < i;%lst-02: ⊦ i < j + i0 ∧ ¬ j0 < j → i < j0 + i0; from specification int-basic2%add-c: ⊦ i + j = j + i; from specification int-basic2%add-a: ⊦ i + j + i0 = (i + j) + i0; from specification int-basic2