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Proof step 1 from proof sub-add-07 (conclusion)

⊦ i + 1 - j = (i - j) + 1

Heuristic simplifier applied rule simplifier

And closed the goal!

Rule argument

Additional information

Used simplifier rules: sub-add-01: ⊦ i + (j - i0) = i + j - i0;%sub-eq: ⊦ i - j = i0 ↔ i = i0 + j;%sub-add-02: ⊦ (i + j) + 1 - i = j + 1;%numadd: ⊦ i + (* j) = i0 + (* j0) ↔ i = i0 + (j0 - j);%add-zero-rev: ⊦ 0 + i = i; from specification int-basic2%add-c: ⊦ i + j = j + i; from specification int-basic2%add-a: ⊦ i + j + i0 = (i + j) + i0; from specification int-basic2