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Proof step 1 from proof sub-less (conclusion)
⊦ 0 < i ∧ 0 < j ∧ 0 < i1 → i ≤ j - i1 → i ≤ j
User applied rule insert rewrite lemma
And obtained the following new goals
Proof step 2
:
⊦ i ≤ j - i0 ↔ i + i0 ≤ j
Proof step 3
:
⊦ 0 < i ∧ 0 < j ∧ 0 < i1 → i + i1 ≤ j → i ≤ j
Rule argument
spec: int-abs inst: name: sub-le-01 seq: ⊦ i ≤ j - i0 ↔ i + i0 ≤ j subst: [i0, j, i] → [i1, j, i] flags: rewrite, current
Additional information
Used terms: i1, j, i