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Proof step 7 from proof sub-less (previous step)

i1 < i1 + i, 0 < i, j < i, 0 < j, 1 < i, 0 < i1 ⊦ j < i + i1

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 8:
⊦ i + j = j + i
Proof step 9:
i1 < i + i1, 0 < i, j < i, 0 < j, 1 < i, 0 < i1 ⊦ j < i + i1

Rule argument

spec: int-basic2 inst: name: add-c seq: ⊦ i + j = j + i subst: [j, i] → [i, i1] flags: rewrite

Additional information

Used simplifier rules: add-c: ⊦ i + j = j + i; from specification int-basic2 Used terms: i, i1