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Proof step 1 from proof sub-minus (conclusion)

⊦ ~ i - ~ j = j - i

Heuristic simplifier applied rule simplifier

And closed the goal!

Rule argument

Additional information

Used simplifier rules: Minus-def: ⊦ ~ i = 0 - i;%sub-sub: ⊦ i - j - i0 = i - j + i0;%sub-zero: ⊦ i + (0 - i0) = i - i0;%sub-sub-04: ⊦ i - (j - j0) = i + j0 - j;%sub-eq: ⊦ i - j = i0 ↔ i = i0 + j;%sub-add-01: ⊦ i + (j - i0) = i + j - i0;%sub-add: ⊦ i + j - i = j;%add-zero-rev: ⊦ 0 + i = i; from specification int-basic2%add-c: ⊦ i + j = j + i; from specification int-basic2%add-a: ⊦ i + j + i0 = (i + j) + i0; from specification int-basic2