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Proof step 1 from proof zero-ge (conclusion)

⊦ 0 ≤ i ∧ 0 ≤ j → 0 ≤ i + j

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 2:
i + j < 0 ⊦ i < 0, j < 0

Rule argument

Additional information

Used simplifier rules: le-def: ⊦ i ≤ j ↔ ¬ j < i;%forward-le-02: ⊦ j < i ∧ i ≤ 0 → j < 0;