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Proof step 4 from proof zero-not (previous step)

i + i0 = 0, i < j ⊦ i < 0, abs(i0) < j

Heuristic weak cut applied rule cut formula

And obtained the following new goals

Proof step 5:
i0 < 0, i + i0 = 0, i < j ⊦ i < 0, abs(i0) < j

Rule argument

fma: i0 < 0

Additional information

Used simplifier rules: Abs-pos: ⊦ ¬ j < 0 → abs(j) = j;%forward-le-05: ⊦ i < j ∧ 0 ≤ i → 0 < j;%zero-06: ⊦ ¬ i < 0 ∧ ¬ j < 0 → (0 = i + j ↔ i = 0 ∧ j = 0); from specification int-basic2%add-a: ⊦ i + j + i0 = (i + j) + i0; from specification int-basic2%add-c: ⊦ i + j = j + i; from specification int-basic2 Used formulas: i0 < 0