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Proof step 1 from proof lf-07 (conclusion)

⊦ ¬ i < i0 ∧ j < i0 → j < i

Heuristic simplifier applied rule simplifier

And closed the goal!

Rule argument

Additional information

Used simplifier rules: l: ⊦ ¬ i < j ↔ ¬ ¬(i = j ∨ j < i);%trans: ⊦ i < j ∧ j < j0 → i < j0;%ls-01: ⊦ i < j → ¬ j < i;