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Proof step 1 from proof ls-succ (conclusion)

⊦ i < j +1 ↔ ¬ j < i

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 2:
⊦ i < j ↔ i +1 = j ∨ i +1 < j
Proof step 3:
⊦ i +1 = j +1 ∨ i +1 < j +1 ↔ ¬ j < i

Rule argument

spec: int-basic1 inst: name: lsrec seq: ⊦ i < j ↔ i +1 = j ∨ i +1 < j subst: [j, i] → [j +1, i] flags: rewrite, current

Additional information

Used terms: j +1, i