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Proof step 20 from proof lst-02 (
previous step
)
1 < i +1 ⊦ i = 0, i = ~1, i < 0, 0 < i
User applied rule insert rewrite lemma
And obtained the following new goals
Proof step 21
:
⊦ 1 < i ↔ 0 < i -1
Rule argument
spec: inst: name: one-less seq: ⊦ 1 < i ↔ 0 < i -1 subst: [i] → [i +1] flags: rewrite, current
Additional information
Used simplifier rules: succpred: ⊦ i +1 -1 = i; Used terms: i +1