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Proof step 22 from proof lst-02 (
previous step
)
∀ j. i0 = j ∨ i0 < j ∨ j < i0 ⊦ i0 +1 = j, i0 +1 < j, j < i0 +1
Heuristic simplifier applied rule simplifier
And obtained the following new goals
Proof step 23
:
∀ j. i0 = j ∨ i0 < j ∨ j < i0 ⊦ i0 +1 = j, i0 +1 < j, j < i0 +1
Rule argument
Additional information