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Proof step 34 from proof lst-02 (previous step)

∀ j. i0 = j ∨ i0 < j ∨ j < i0 ⊦ j +1 = i0, i0 -1 < j, j < i0 -1

Heuristic elimination applied rule insert elim lemma

And obtained the following new goals

Proof step 35:
⊦ i = j -1 ↔ j = i +1
Proof step 36:
i0 = i +1, ∀ j. i0 = j ∨ i0 < j ∨ j < i0 ⊦ j +1 = i0, i < j, j < i

Rule argument

spec: int-basic1 inst: name: elim-pred seq: ⊦ i = j -1 ↔ j = i +1 subst: [j, i] → [i0, i] flags: rewrite, current

Additional information

Used terms: i0, i