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Proof step 37 from proof lst-02 (previous step)

∀ j. i +1 = j ∨ i +1 < j ∨ j < i +1 ⊦ j = i, i < j, j < i

User applied rule all left

And obtained the following new goals

Proof step 38:
i +1 = j +1 ∨ i +1 < j +1 ∨ j +1 < i +1 ⊦ j = i, i < j, j < i

Rule argument

pos: left 1 terms: j +1 abort: F discard: T computed: F

Additional information

Used terms: j +1