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Proof step 39 from proof lst-02 (previous step)

i +1 < j +1 ∨ j +1 < i +1 ⊦ j = i, i < j, j < i

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 40:
⊦ i +1 < j ↔ i < j -1
Proof step 41:
i < j +1 -1 ∨ j +1 < i +1 ⊦ j = i, i < j, j < i

Rule argument

spec: int-basic1 inst: name: lssucc seq: ⊦ i +1 < j ↔ i < j -1 subst: [j, i] → [j +1, i] flags: rewrite, current

Additional information

Used terms: j +1, i