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Proof step 6 from proof lst-02 (previous step)

j0 < 0 ⊦ j0 = ~1, 0 = j0, j0 +1 < 0, 0 < j0 +1

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 7:
⊦ i < j ↔ i +1 = j ∨ i +1 < j

Rule argument

spec: inst: name: lsrec seq: ⊦ i < j ↔ i +1 = j ∨ i +1 < j subst: [j, i] → [0, j0] flags: rewrite, current

Additional information

Used simplifier rules: numeral: ⊦ i +1 = (* j) ↔ i = j -1; Used terms: 0, j0