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Proof step 4 from proof minus-one (previous step)

i +1 = 0 ∨ i +1 < 0, ~2 < i ⊦ i = ~1

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 5:
~2 < i, i < ~1, i < 0 ⊦ i = ~1

Rule argument

Additional information

Used simplifier rules: numeral: ⊦ i +1 = (* j) ↔ i = j -1;%numeral-01: ⊦ i +1 < (* j) ↔ i < j -1;%numlsf: ⊦ i < (* j) ∧ j < 0 → i < 0;