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Proof step 5 from proof add-in (previous step)

(i1 + 1) + j = (i1 + 1) + i0, i1 + 1 + j = i1 + 1 + i0 → 1 + j = 1 + i0, ∀ j, i0. i1 + j = i1 + i0 → j = i0 ⊦ j = i0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

Additional information

Used simplifier rules: add-a: ⊦ i + j + i0 = (i + j) + i0;%add-c: ⊦ i + j = j + i;