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Proof step 1 from proof ex-oddeven (conclusion)

⊦ ∃ i. i + i = j ∨ i + i + 1 = j

User applied rule structural induction

And obtained the following new goals

Proof step 2:
⊦ ∃ i. i + i = 0 ∨ i + i + 1 = 0
Proof step 4:
∃ i. i + i = j0 ∨ i + i + 1 = j0 ⊦ ∃ i. i + i = j0 +1 ∨ i + i + 1 = j0 +1
Proof step 10:
∃ i. i + i = j0 ∨ i + i + 1 = j0 ⊦ ∃ i. i + i = j0 -1 ∨ i + i + 1 = j0 -1

Rule argument

indvar: j

Additional information

Used simplifier rules: int generated by 0, +1, -1;;