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Proof step 6 from proof ex-oddeven (
previous step
)
i + i = j0 ⊦ ∃ i0. i0 + i0 = j0 + 1 ∨ i0 + i0 = j0
Heuristic simplifier applied rule simplifier
And obtained the following new goals
Proof step 7
:
⊦ ∃ i0. i0 + i0 = (i + i) + 1 ∨ i0 + i0 = i + i
Rule argument
Additional information