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Proof step 6 from proof ls-01 (previous step)

∀ j, i0. i1 + j < i1 + i0 ↔ j < i0 ⊦ (i1 + j)+1 < (i1 + i0)+1 ↔ j < i0

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 7:
⊦ i +1 < j +1 ↔ i < j
Proof step 8:
∀ j, i0. i1 + j < i1 + i0 ↔ j < i0 ⊦ i1 + j < i1 + i0 ↔ j < i0

Rule argument

spec: int-basic1 inst: name: ls-succ-02 seq: ⊦ i +1 < j +1 ↔ i < j subst: [j, i] → [i1 + i0, i1 + j] flags: rewrite

Additional information

Used terms: i1 + i0, i1 + j