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Proof step 5 from proof lst-02 (previous step)

∀ i, j, j0. i < j + i1 → i < j0 + i1 ∨ j0 < j, i < j + i1 -1 ⊦ i < j0 + i1 -1, j0 < j

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

Additional information

Used simplifier rules: add-pred-01: ⊦ i -1 + j = (i + j)-1;%add-a: ⊦ i + j + i0 = (i + j) + i0;%add-c: ⊦ i + j = j + i;%succ-01: ⊦ i +1 = i + 1;%ls-pred: ⊦ i < j -1 ↔ i +1 < j; from specification int-basic1