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Proof step 1 from proof mone-02 (conclusion)

⊦ i + 1 = ~1 ↔ i + 1 + 1 = 0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 2:
⊦ i + 1 = ~1 ↔ 2 + i = 0

Rule argument

Additional information

Used simplifier rules: add-a: ⊦ i + j + i0 = (i + j) + i0;%add-c: ⊦ i + j = j + i;