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Proof step 1 from proof neq-01 (conclusion)

⊦ i0 < i + j0 ∧ ¬ j < j0 → i0 ≠ i + j

Heuristic simplifier applied rule simplifier

And closed the goal!

Rule argument

Additional information

Used simplifier rules: ls-01: ⊦ i + j < i + i0 ↔ j < i0;%add-a: ⊦ i + j + i0 = (i + j) + i0;%add-c: ⊦ i + j = j + i;