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Proof step 2 from proof nls (previous step)

i + i0 < j + j0 ⊦ i0 < j0, i < j

User applied rule cut formula

And obtained the following new goals

Proof step 3:
i + i0 < j + j0 ⊦ i = j, i0 < j0, i < j

Rule argument

fma: i = j

Additional information

Used simplifier rules: ls-01: ⊦ i + j < i + i0 ↔ j < i0;%add-a: ⊦ i + j + i0 = (i + j) + i0;%add-c: ⊦ i + j = j + i;%irref: ⊦ ¬ i < i; from specification int-basic1 Used formulas: i = j