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Proof step 5 from proof nls (previous step)

i + i0 < j + j0, j < i ⊦ i0 = j0, i0 < j0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 6:
i + i0 < j + j0, j < i, j0 < i0 ⊦

Rule argument

Additional information

Used simplifier rules: ls-01: ⊦ i < j → ¬ j < i; from specification int-basic1%lst-01: ⊦ ¬ i < j → (i ≠ j ↔ j < i); from specification int-basic1