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Proof step 1 from proof not-zero-pos (conclusion)

⊦ 0 < i ∧ 0 < j → i + j ≠ 0

Heuristic simplifier applied rule simplifier

And closed the goal!

Rule argument

Additional information

Used simplifier rules: zero-04: ⊦ 0 < i ∧ 0 < j → 0 ≠ i + j;%add-a: ⊦ i + j + i0 = (i + j) + i0;%add-c: ⊦ i + j = j + i;