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Proof step 1 from proof pls-01 (conclusion)

¬ i < 0, ¬ j < 0 ⊦ ¬ i + j < 0

Heuristic simplifier applied rule simplifier

And closed the goal!

Rule argument

Additional information

Used simplifier rules: ls: ⊦ i + j < j ↔ i < 0;%add-a: ⊦ i + j + i0 = (i + j) + i0;%lf-04: ⊦ ¬ j < i ∧ j < i0 → i < i0; (forward) from specification int-basic1%trans: ⊦ i < j ∧ j < j0 → i < j0; (forward) from specification int-basic1%lf-01: ⊦ i < j ∧ j < i0 → i +1 < i0; (forward) from specification int-basic1%lf-07: ⊦ ¬ i < i0 ∧ j < i0 → j < i; (forward) from specification int-basic1