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Proof step 1 from proof pls-03 (conclusion)

¬ i < j, ¬ i0 < j0 ⊦ ¬ i + i0 < j + j0

Heuristic simplifier applied rule simplifier

And closed the goal!

Rule argument

Additional information

Used simplifier rules: nls: ⊦ ¬ i < j ∧ ¬ i0 < j0 → ¬ i + i0 < j + j0;%add-a: ⊦ i + j + i0 = (i + j) + i0;%add-c: ⊦ i + j = j + i;