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Proof step 2 from proof pls (previous step)

∀ j, i0, j0. i1 < j ∧ i0 < j0 → i1 + i0 < j + j0, i1 +1 < j, i0 < j0 ⊦ i1 +1 + i0 < j + j0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

Additional information

Used simplifier rules: succ-01: ⊦ i +1 = i + 1;