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Proof step 6 from proof pls (previous step)

i0 < j0, i1 < j + 1, i1 < j + 1 ∧ i1 < j0 → i1 + i1 < (j + 1) + j0, ∀ j, i0, j0. i1 < j ∧ i0 < j0 → i1 + i0 < j + j0 ⊦ i0 + i1 < (j + j0) + 1

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

Additional information