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Proof step 8 from proof plst-01 (previous step)

i + j1 < j + j1, i + j1 < j + j0, i + i0 < j + j0, j0 < j1, i1 < i0 ⊦ i + i1 < j + j1

User applied rule insert lemma

And obtained the following new goals

Proof step 9:
⊦ i + j < i0 ∧ j0 < j → i + j0 < i0

Rule argument

spec: int-basic2 inst: name: lst-04 seq: ⊦ i + j < i0 ∧ j0 < j → i + j0 < i0 subst: [i, j, i0, j0] → [i, i0, j + j1, i1] flags: current, []

Additional information

Used simplifier rules: ls-01: ⊦ i + j < i + i0 ↔ j < i0;%add-a: ⊦ i + j + i0 = (i + j) + i0;%add-c: ⊦ i + j = j + i;%lst-01: ⊦ i < j + i0 ∧ j < j0 → i < j0 + i0; Used terms: i, i0, j + j1, i1