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Proof step 1 from proof succ (conclusion)

⊦ (i + j)+1 = i ↔ j +1 = 0

Heuristic simplifier applied rule simplifier

And closed the goal!

Rule argument

Additional information

Used simplifier rules: succ-01: ⊦ i +1 = i + 1;%eq: ⊦ i = i + j ↔ j = 0;%add-a: ⊦ i + j + i0 = (i + j) + i0;%add-c: ⊦ i + j = j + i;