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Proof step 2 from proof zero-07 (previous step)

i + i = 0 ⊦ i = 0

User applied rule cut formula

And closed the goal!

Rule argument

fma: i < 0

Additional information

Used simplifier rules: zero: ⊦ i < 0 ∧ j < 0 → i + j ≠ 0;%add-a: ⊦ i + j + i0 = (i + j) + i0;%add-c: ⊦ i + j = j + i;%zero-06: ⊦ ¬ i < 0 ∧ ¬ j < 0 → (0 = i + j ↔ i = 0 ∧ j = 0);%add-a: ⊦ i + j + i0 = (i + j) + i0;%add-c: ⊦ i + j = j + i; Used formulas: i < 0